d^2+3d-7=0

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Solution for d^2+3d-7=0 equation:


Simplifying
d2 + 3d + -7 = 0

Reorder the terms:
-7 + 3d + d2 = 0

Solving
-7 + 3d + d2 = 0

Solving for variable 'd'.

Begin completing the square.

Move the constant term to the right:

Add '7' to each side of the equation.
-7 + 3d + 7 + d2 = 0 + 7

Reorder the terms:
-7 + 7 + 3d + d2 = 0 + 7

Combine like terms: -7 + 7 = 0
0 + 3d + d2 = 0 + 7
3d + d2 = 0 + 7

Combine like terms: 0 + 7 = 7
3d + d2 = 7

The d term is 3d.  Take half its coefficient (1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
3d + 2.25 + d2 = 7 + 2.25

Reorder the terms:
2.25 + 3d + d2 = 7 + 2.25

Combine like terms: 7 + 2.25 = 9.25
2.25 + 3d + d2 = 9.25

Factor a perfect square on the left side:
(d + 1.5)(d + 1.5) = 9.25

Calculate the square root of the right side: 3.041381265

Break this problem into two subproblems by setting 
(d + 1.5) equal to 3.041381265 and -3.041381265.

Subproblem 1

d + 1.5 = 3.041381265 Simplifying d + 1.5 = 3.041381265 Reorder the terms: 1.5 + d = 3.041381265 Solving 1.5 + d = 3.041381265 Solving for variable 'd'. Move all terms containing d to the left, all other terms to the right. Add '-1.5' to each side of the equation. 1.5 + -1.5 + d = 3.041381265 + -1.5 Combine like terms: 1.5 + -1.5 = 0.0 0.0 + d = 3.041381265 + -1.5 d = 3.041381265 + -1.5 Combine like terms: 3.041381265 + -1.5 = 1.541381265 d = 1.541381265 Simplifying d = 1.541381265

Subproblem 2

d + 1.5 = -3.041381265 Simplifying d + 1.5 = -3.041381265 Reorder the terms: 1.5 + d = -3.041381265 Solving 1.5 + d = -3.041381265 Solving for variable 'd'. Move all terms containing d to the left, all other terms to the right. Add '-1.5' to each side of the equation. 1.5 + -1.5 + d = -3.041381265 + -1.5 Combine like terms: 1.5 + -1.5 = 0.0 0.0 + d = -3.041381265 + -1.5 d = -3.041381265 + -1.5 Combine like terms: -3.041381265 + -1.5 = -4.541381265 d = -4.541381265 Simplifying d = -4.541381265

Solution

The solution to the problem is based on the solutions from the subproblems. d = {1.541381265, -4.541381265}

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